| "the amount of energy we are using to drive the pump and the fan, which is constant given the fact they have their respective impedance and are being supplied a consistent voltage. " the electric water pump should draw more current (use more power) even at a constant voltage. As the load increases. In a close circuit test like yours, the increase in load could only come from a radiator with more resistance to flow. because the pump draws more power to compensate for the increase in load, it will maintain the flow through the rad, and it won't show up in your test where only temp is measured. If on the other hand, the flow potential of the pump were fixed, then I would expect to see a more poorly flowing rad to perform more poorly at heat dissipation. in any case though I think your tests will really give use all a lot more insight. I appreciate what your doing here, and that your sharing your results with us.
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